章节大纲

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    Luke is making cookies to share with his teachers for the holidays. He has decided to make three different types of cookies. For the first type of cookie he needs  3 4  cups of sugar. For the second type of cookie he needs  1 1 3  cups of sugar. For the third type of cookie he needs  2 1 2  cups of sugar.  His mom just told him that they only have about 5 cups of sugar in the house. How can Luke figure out if he will have enough sugar to make all of his cookies?
    ::Luke正在做饼干,以便和老师们分享假期。他决定做三种不同的饼干。 对于第一种饼干,他需要34杯糖。对于第二种饼干,他需要113杯糖。对于第三种饼干,他需要212杯糖。他的妈妈刚刚告诉他,家里只有5杯糖。Luke怎么弄清楚他是否有足够的糖做他的饼干?

    In this concept, you will learn how to add fractions and mixed numbers.
    ::在这个概念中,你会学会如何增加分数和混合数字。

    Adding Fractions and Mixed Numbers
    ::添加分数和混合数字

    fraction  describes a part of a whole number. The number written below the bar in a fraction is the  denominator , and it tells you how many parts the whole is divided into. The number above the bar in a fraction is the  numerator , and it tells you how many parts of the whole you have.   are fractions that describe the same part of a whole.
    ::一个分数描述整个数字的一部分。 分数中写在条下的一个分数是分母, 它会告诉您整个的分母。 条上的一个分数是分子, 它会告诉你整体的多少部分。 分数是描述整个的同一个部分的分数。

    To add fractions:
    ::添加分数 :

    1. Rewrite each fraction as an equivalent fraction so that the denominators are the same.
      ::将每一分数重写为相等的分数,以便分母相同。
    2. Add the numerators of the equivalent fractions. Keep the denominator the same.
      ::添加等效分数的分子。保持分母不变。
    3. Simplify  your answer.
      ::简化您的答案 。

    Here is an example.
    ::举一个例子。

    Find the  sum  of  1 2  and  1 3 .
    ::查找12和13之和。

    First, find a  common denominator . You are looking for a number that is a  multiple  of both 2 and 3. The product of 2 and 3 is 6 and in this case that is the  least common multiple  of 2 and 3.
    ::首先,找到一个共同的分母。您正在寻找一个数字,该数字是2和3的倍数。2和3的产值是6,在此情况下,是2和3的最小公倍数。

    Now, rewrite each fraction as an equivalent fraction with a denominator of 6. Remember to always multiply the numerator and denominator of the fraction by the same number. 
    ::现在, 将每个分数重写为等值分数, 分母为 6 。 记住始终要将分数的分子和分母乘以相同数字 。

    1 2 = 1 × 3 2 × 3 = 3 6 1 3 = 1 × 2 3 × 2 = 2 6

    Next, add the equivalent fractions. You will add the numerators and keep the denominator the same.
    ::下一步,添加等效分数。您将添加分子,并将分母保持原样。

    3 6 + 2 6 = 5 6

    Finally, check to make sure your answer is in  simplest form 5 6  is in simplest form because 5 and 6 do not have any common  factors  besides 1.
    ::最后,检查以确保您的答复最简单。 5 6 最简单, 因为 5 和 6 除了 1 以外没有任何共同因素。

    The answer is  1 2 + 1 3 = 5 6 .
    ::答案是 1 2+1 3 = 5 6 。

    Numbers that consist of a whole number and a fraction are called  mixed numbers .
    ::由整数和分数组成的数字称为混合数。

    To add mixed numbers:
    ::增加混合数字:

    1. Add the fractional parts of the mixed numbers.
      ::添加混合数字的分数部分。
    2. Add the whole parts of the mixed numbers.
      ::加上混合数字的整个部分。
    3. Add the sum of the fractional parts to the sum of the  whole numbers .
      ::将分部分的总和加到整个数字的总和中。
    4. Simplify your answer.
      ::简化您的答案 。

    Here is an example.
    ::举一个例子。

    Add  3 4 + 2 1 3 .
    ::加3 4 + 2 1 3 。

    First, add the fractional parts:  3 4 + 1 3 . Find a common denominator. You are looking for a number that is a multiple of both 4 and 3. 12 is the least common multiple of 4 and 3.
    ::首先,添加分部分: 3, 4+1, 3。 找到一个共同的分母。 您正在寻找一个数字, 该数字是 4 和 3. 的倍数, 4 和 3. 12 是 4 和 3 中最不常见的 4 和 3 的 倍数 。

    Now, rewrite each fraction as an equivalent fraction with a denominator of 12.
    ::现在,将每个分数重写为相等的分数,分母为12。

    3 4 = 3 × 3 4 × 3 = 9 12 1 3 = 1 × 4 3 × 4 = 4 12

    Next, add the equivalent fractions. You will add the numerators and keep the denominator the same. Rewrite your result as a  mixed number .
    ::下一步,添加相等的分数。您将添加数组,并将分母保持不变。将结果重写为混合数。

    9 12 + 4 12 = 13 12 = 1 1 12

    Now, add the whole part of the original mixed number to your sum so far.
    ::现在,把原来混合数字的整部分 加入到目前为止的总数中。

    2 + 1 1 12 = 3 1 12

    Finally, check to make sure your answer is in simplest form.  3 1 12  is in simplest form because 1 and 12 do not have any common factors besides 1.
    ::最后,检查以确保你的答复最简单。 3, 1, 12, 最简单, 因为1, 12 除了1, 没有任何共同因素。

    The answer is  3 4 + 2 1 3 = 3 1 12 .
    ::答案是3 4 + 2 1 3 = 3 1 12。

    Examples
    ::实例

    Example 1
    ::例1

    Earlier, you were given a problem about Luke and his cookies.
    ::早些时候,你被问及 卢克和他的饼干的问题。

    He is making three different types of cookies. For the first type of cookie he needs  3 4  cups of sugar, for the second type of cookie he needs  1 1 3  cups of sugar, and for the third type he needs  2 1 2  cups of sugar. His mom told him that they only have about 5 cups of sugar in the house. Luke needs to make sure he has enough sugar to make all of his cookies.
    ::他正在做三种不同的曲奇。 对于第一种曲奇,他需要34杯糖,第二种曲奇需要13杯糖,第三种曲奇需要2,12杯糖。他妈妈告诉他,家里只有5杯糖。卢克需要确保他有足够的糖做他所有的曲奇。

    To figure this out, Luke will need to add the three amounts of sugar and see if he needs less than 5 cups.
    ::卢克需要加三批糖 看看他是否需要不到五杯

    First, add the fractional parts of the mixed numbers. Find a common denominator. You are looking for a number that is a multiple of 4, 3, and 2. 12 is the least common multiple of 4, 3, and 2.
    ::首先,添加混合数字的分数部分。 找到一个共同的分母。 您正在寻找一个数字, 它的乘数是 4 、 3 和 2. 2 。 12 是 4 、 3 和 2 中最不常见的乘数是 4 、 3 和 2 。

    Now, rewrite each fraction as an equivalent fraction with a denominator of 12.
    ::现在,将每个分数重写为相等的分数,分母为12。

    3 4 = 3 × 3 4 × 3 = 9 12 1 3 = 1 × 4 3 × 4 = 4 12 1 2 = 1 × 6 2 × 6 = 6 12

    Next, add the equivalent fractions. You will add the numerators and keep the denominator the same. Rewrite your result as a mixed number.
    ::下一步,添加相等的分数。您将添加数组,并将分母保持不变。将结果重写为混合数。

    9 12 + 4 12 + 6 12 = 19 12 = 1 7 12

    Now, add the whole parts of the original mixed numbers.
    ::现在,加上原来的混合数字的整部分。

    1 + 2 = 3

    Next, add the sum of the fractional parts to the sum of the whole numbers.
    ::下一步,在整数的总和中加入分部分的和。

    3 + 1 7 12 = 4 7 12

    Luke needs  4 7 12  cups of sugar.
    ::卢克需要4 7 12杯糖

    The answer is that, because Luke needs  4 7 12  cups of sugar and he has 5 cups of sugar, he will have enough sugar to make all three types of cookies.
    ::答案是,因为卢克需要4 7 12杯糖, 他有5杯糖, 他有足够的糖来做三种饼干。

    Example 2
    ::例2

    Donte is making a costume with blue, red, and black fabric. He has  6 1 2  yards of blue fabric,  3 2 3  yards of red fabric, and  5 4 5  yards of black fabric. How many yards of fabric does Donte have all together?
    ::唐特正在做一件蓝色、红色和黑色布料的服装。 他有612码的蓝色布料,323码的红色布料,545码的黑色布料。 唐特一共有多少码的布料?

    In  order  to solve this problem, you need to add the three given mixed numbers.
    ::为了解决这个问题,您需要添加三个给定的混合数字。

    First, add the fractional parts of the mixed numbers. Find a common denominator. You are looking for a number that is a multiple of 2, 3, and 5. 30 is the least common multiple of 2, 3, and 5.
    ::首先,添加混合数字的分数部分。 找到一个共同的分母。 您正在寻找一个数字, 数字的乘数是 2, 3, 5, 5, 30 是 2, 3, 5 中最不常见的乘数是 2, 3, 5 。

    Now, rewrite each fraction as an equivalent fraction with a denominator of 30.
    ::现在,将每一分数重写为30分母的等同分数。

    1 2 = 1 × 15 2 × 15 = 15 30 2 3 = 2 × 10 3 × 10 = 20 30 4 5 = 4 × 6 5 × 6   = 24 30

    Next, add the equivalent fractions. You will add the numerators and keep the denominator the same. Rewrite your result as a mixed number.
    ::下一步,添加相等的分数。您将添加数组,并将分母保持不变。将结果重写为混合数。

    15 30 + 20 30 + 24 30 = 59 30 = 1 29 30

    Now, add the whole parts of the original mixed numbers.
    ::现在,加上原来的混合数字的整部分。

    6 + 3 + 5 = 14

    Next, add the sum of the fractional parts to the sum of the whole numbers.
    ::下一步,在整数的总和中加入分部分的和。

    14 + 1 29 30 = 15 29 30

    Finally, check to make sure your answer is in simplest form.  15 29 30  is in simplest form because 29 and 30 do not have any common factors besides 1.
    ::最后,检查以确保您的答复最简单。 15 29 30 最简单, 因为 29 和 30 除了 1 以外没有任何共同因素。

    The answer is that Donte has  15 29 30  yards of fabric all together.
    ::答案是 唐特有152930码的布料

    Example 3
    ::例3

    Add  9 1 2 + 22 1 4 .
    ::加9 1 2 + 22 1 4 。

    First, add the fractional parts of the mixed numbers. Find a common denominator. You are looking for a number that is a multiple of both 2 and 4. 4 is the least common multiple of 2 and 4.
    ::首先,添加混合数字的分部分。 找到一个共同的分母。 您正在寻找一个数字, 数字是2和4的倍数, 4是2和4中最不常见的倍数。

    Now, rewrite each fraction as an equivalent fraction with a denominator of 4.
    ::现在,将每一分数重写为等效分数,分母为4。

    1 2 = 1 × 2 2 × 2 = 2 4 1 4 = 1 4

    Next, add the equivalent fractions. You will add the numerators and keep the denominator the same.
    ::下一步,添加等效分数。您将添加分子,并将分母保持原样。

    2 4 + 1 4 = 3 4

    Now, add the whole parts of the original mixed numbers.
    ::现在,加上原来的混合数字的整部分。

    9 + 22 = 31

    Next, add the sum of the fractional parts to the sum of the whole numbers.
    ::下一步,在整数的总和中加入分部分的和。

    31 + 3 4 = 31 3 4

    Finally, check to make sure your answer is in simplest form.  31 3 4  is in simplest form because 3 and 4 do not have any common factors besides 1.
    ::最后,检查以确保您的答复最简单。 31 3 4 最简单, 因为 3 和 4 除了1 以外没有任何共同因素。

    The answer is  9 1 2 + 22 1 4 = 31 3 4 .
    ::答案是 9 1 2 + 22 1 4 = 31 3 4 。

    Example 4
    ::例4

    Add  2 1 3 + 8 2 3 .
    ::加2 1 3 3 + 8 2 3 。

    First, add the fractional parts of the mixed numbers. You will add the numerators and keep the denominator the same. Rewrite your result as a whole number.
    ::首先,添加混合数字的分数部分。您将添加分子,并保持分母不变。将结果重写为整数。

    1 3 + 2 3 = 3 3 = 1

    Now, add the whole parts of the original mixed numbers.
    ::现在,加上原来的混合数字的整部分。

    2 + 8 = 10

    Next, add the sum of the fractional parts to the sum of the whole numbers.
    ::下一步,在整数的总和中加入分部分的和。

    10 + 1 = 11

    The answer is  2 1 3 + 8 2 3 = 11 .
    ::答案是 2 1 3 + 8 2 3 = 11 。

    Example 5
    ::例5

    Add  5 1 3 + 1 7 .
    ::加5 1 3 + 1 7 。

    First, add the fractional parts of the mixed numbers. Find a common denominator. You are looking for a number that is a multiple of both 3 and 7. 21 is the least common multiple of 3 and 7.
    ::首先,添加混合数字的分部分。 找到一个共同的分母。 您正在寻找一个3和7的倍数, 21是3和7中最不常见的3和7的倍数。

    Now, rewrite each fraction as an equivalent fraction with a denominator of 21.
    ::现在,将每一分数重写为等效分数,分母为21。

    1 3 = 1 × 7 3 × 7 = 7 21 1 7 = 1 × 3 7 × 3 = 3 21

    Next, add the equivalent fractions. You will add the numerators and keep the denominator the same.
    ::下一步,添加等效分数。您将添加分子,并将分母保持原样。

    7 21 + 3 21 = 10 21

    Now, add the sum of the fractional parts to the original whole number.
    ::现在,在原整数中加入分部分的总和。

    5 + 10 21 = 5 10 21

    Finally, check to make sure your answer is in simplest form.  5 10 21  is in simplest form because 10 and 21 do not have any common factors besides 1.
    ::最后,检查以确保你的答复最简单。 5 10 21 最简单, 因为 10 和 21 除了1 以外没有任何共同因素。

    The answer is  5 1 3 + 1 7 = 5 10 21 .
    ::答案是5 1 3+1 7 = 5 10 21。

    Review
    ::回顾

    Add the following fractions and mixed numbers. Simplify your answers.
    ::添加以下分数和混合数字。简化您的答案。

    1. 3 7 + 1 14  
    2. 3 4 + 1 3  
    3. 2 5 + 3 10  
    4. 1 9 + 1 6  
    5. 2 3 5 + 17 20  
    6. 8 5 12 + 2 1 6  
    7. 1 2 3 + 1 3 4  
    8. 2 1 5 + 4 14 15  
    9. 2 1 5 + 4 2 15  
    10. 12 1 5 + 4 6 15  
    11. 2 3 4 + 4 1 6  
    12. 3 4 10 + 6 1 9  
    13. 2 1 30 + 12 15  
    14. 4 1 2 + 14 4 5  
    15. 16 8 9 + 14 9 12  

    Review (Answers)
    ::回顾(答复)

    Click   to see the answer key or go to the Table of Contents and click on the Answer Key under the 'Other Versions' option.
    ::单击可查看答题键, 或转到目录中, 单击“ 其他版本” 选项下的答题键 。

    Resources
    ::资源