课程： 14.2 答复----第2章:一个变量的线性等同和不平等

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选择节回答 - Cch 2:一个变量的线性等同和不平等

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回答 - Cch 2:一个变量的线性等同和不平等
Section 2.2: Solving One-Step Equations
::第2.2节:解决单级等号

Review
::回顾

$\begin{align*}2\end{align*}$

$\begin{align*}\frac{3}{8}\end{align*}$

$\begin{align*}39.03\end{align*}$

$\begin{align*}4\sqrt{5}\end{align*}$

$\begin{align*}\text{-}56\end{align*}$

$\begin{align*}11\end{align*}$

$\begin{align*}42\end{align*}$

$\begin{align*}8\end{align*}$

False
::假假

True
::真实

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::探索更多

$\begin{align*}$35\end{align*}$

1,760 lines of code
::1 760条代码线

$\begin{align*}$28,\!800\end{align*}$

$\begin{align*}2,533\frac{1}{3}\end{align*}$ mg, or approximately 2,533.3 mg
::2,53313毫克,或约2,53.3毫克

The multiplicative inverse of $\begin{align*}\text{-}\frac{5}{4}\end{align*}$ is $\begin{align*}\text{-}\frac{4}{5}\end{align*}$ .
::乘数反对 -54是 -45。

17.5 mL
::17.5毫升

Section 2.3: Solving Two-Step Equations
::第2.3节:解决两层两层

Review
::回顾

x = -6
::x = -6 = -6

b = 2
::b = 2

p = 6
::p = 6

m = -2
::m = -2

s = -14
::s = -14 = -14

r = 75
::r = 75

x = $\begin{align*}\frac{4}{5}\end{align*}$

::x = 45

d = 28
::d = 28

False
::假假

True
::真实

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::探索更多

The plumber worked for 1 hour and 45 minutes. He ended his work at 11:15 a.m.
::水管工工作了1小时45分钟,上午11时15分结束工作。

Approximately 0.055, or 5.5%.
::约0.055,即5.5%。

3,030 students
::3 030名学生

32 players
::32个玩家

a. $\begin{align*}\frac{86}{15}\end{align*}$ b. $\begin{align*}\frac{21}{40}\end{align*}$
::a. 8615 b. 2140

Section 2.4: Solving Multi-Step Equations

::第2.4节:解决多级数

Review
::回顾

x = -2
::x = -2

y = 4
::y=4 y=4

w = 29
::w = 29

$\begin{align*}s = \sqrt{6} - \sqrt{2}\end{align*}$
::62

t = 1
::t = 1

r = $\begin{align*}\frac{2}{5}\end{align*}$
::r = 25

p = -65
::p=-65 =-65

q = 2
::q=2

n = -21
::n= -21

m = -4
::m = -4

h = -12
::h = - 12

d = 1
::d=1 =1

x = 5
::x = 5

x = 15
::x = 15

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::探索更多

Resistance of the new component is 34Ω.
::对新组成部分的抵制是34日。

a. 9. b. 42. c. Answers will vary. One option is to subtract 2 and then multiply the result by 6.
::a. 9.b. 42.c. 答复将有所不同,一种选择是减去2,然后乘以6。

x = $\begin{align*}\text{-}\frac{1}{16}\end{align*}$

::x = - 116

26 months
::26个月26个月

Section 2.5: Solving Equations for a Variable (Literal Equations)

::第2.5节:变量的溶解等量(标准等量)

Review
::回顾

$\begin{align*}r=\frac{C}{2\pi }\end{align*}$
::r= C2

$\begin{align*}h=\frac{A}{b}\end{align*}$
::h=Ab =Ab

$\begin{align*}l=\frac{1}{2}(P-2w)\end{align*}$
::l=12(P-2w)

$\begin{align*}b=\frac{2A}{h}\end{align*}$
::b=2A小时

$\begin{align*}{b}_{1} = \frac{2A}{h}-{b}_{2}\end{align*}$
::b1=2Ah-b2

$\begin{align*}m = 30 - \frac{5}{6}n\end{align*}$
::m=30-56n

$\begin{align*}n=36-\frac{6}{5}m\end{align*}$
::n=36-65m

30° C
::30°C 30°C

3.5%

$\begin{align*}h=\frac{s-2\pi {r}^{2}}{2\pi r} = \frac{s}{2\pi r}-r\end{align*}$
::h=s=-2r22r=s2r-r

4 cm
::4厘米 4厘米

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$\begin{align*}y = \frac{15}{8}x - 15\end{align*}$
::y=158x-15

$\begin{align*}{h}_{cylinder} = \frac{v}{25\pi }\ge \frac{v}{100} = {h}_{rectangular \ prism},\end{align*}$ so the cylinder is taller.
::hcylinder=v25v100=长方形棱柱,因此圆柱体更高。

Since the length of the wall is fixed, the height doubles as well.
::由于隔离墙的长度是固定的,高度也加倍。

Approximately 10 feet
::大约10英尺左右

15 feet
::15英尺 15英尺

Section 2.6: Solving One- and Two-Step Inequalities
::第2.6节:解决一和二分不平等

Review
::回顾

$\begin{align*}x > \text{-}11\end{align*}$
::x >- 11

$\begin{align*}11> b\end{align*}$
::11>b 11>b

$\begin{align*}m \ge 7\end{align*}$
::7 立方米

$\begin{align*}\text{-}4>d\end{align*}$
::-4>d 4>d

$\begin{align*}f\le 4\end{align*}$
::f§4

$\begin{align*}v > \text{-}3\end{align*}$
::v>-3

$\begin{align*}q\ge 14\end{align*}$

::q14

$\begin{align*}u > 24\end{align*}$
::u>24

$\begin{align*}\text{-}14< s\end{align*}$
::-14 < 秒

$\begin{align*}x\ge \frac{3}{2}\end{align*}$
::x% 32 个

No
::否无

No
::否无

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::探索更多

14 goldfish
::14条金鱼

18 flowers
::18花花

5 years and 9 months
::5年零9个月

$93.86

$\begin{align*}I \ge 0.2(18 \ mg)\end{align*}$ or $\begin{align*}I \ge 3.6 \ mg\end{align*}$
::I0.2(18毫克)或I3.6毫克

Section 2.7: Solving Multi-Step Inequalities
::第2.7节:解决多重不平等

Review
::回顾

$\begin{align*}x\le \text{-}5\end{align*}$
::x__-5

$\begin{align*}x> \frac{2}{3}\end{align*}$
::x>23

$\begin{align*}p> \frac{2,\!051}{520}\end{align*}$
::2,051520 p>2,051520

$\begin{align*}u \ge 13\end{align*}$
::十三号

$\begin{align*}s > \text{-}4\end{align*}$
::秒 > - 4

$\begin{align*}\text{-}\frac{19}{2} > q \end{align*}$
::-192>q

$\begin{align*}v \ge \frac{7}{2}\end{align*}$
::v72

$\begin{align*}r \le \frac{4}{3}\end{align*}$
::r 瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦瓦

$\begin{align*}d < 6\end{align*}$
::d < 6

$\begin{align*}x < \text{-}1\end{align*}$
::x <-1

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19 containers
::19个集装箱

≤ 8 students
::8名学生

17 students
::17名学生

6 flowers (at 5 you would break even)
::6朵花(5朵花,

The side of the inequality does not matter. You get the same answer by either approach.
::不平等的一方无关紧要,无论采取哪种方法,你都会得到相同的答案。

The 3x terms on each side cancel each other out. There is no solution, since $\begin{align*}\text{-}7 > 9 \end{align*}$ is never true.
::双方的3x条件相互取消。没有解决办法, 因为 - 7> 9 永远不会是真实的。

Section 2.8: Solving Compound Inequalities

::第2.8节:解决复合物不平等问题

Review
::回顾

$\begin{align*}x < \text{-}\frac{13}{2} = \text{-}6.5\end{align*}$ or $\begin{align*}x \ge \text{-}3\end{align*}$
::x-132=-6.5 或 x__-3

$\begin{align*}x > \text{-}3 \end{align*}$ or $\begin{align*}x \le \text{-}6\end{align*}$
::x-3 或 x__-6

$\begin{align*}x \le \text{-}48\end{align*}$ or $\begin{align*}x > 14\end{align*}$
::x- 48 或 x>14

$\begin{align*}x < \text{-}\frac{1}{2}\end{align*}$ or $\begin{align*}x > \sqrt{3}\end{align*}$
::x - 12 或 x% 3

$\begin{align*}\text{-}2< x \le 11\end{align*}$
::-2<x=11 -2<x=11

$\begin{align*}0 < x < 20\end{align*}$
::0<x<20>

$\begin{align*}3 \le x < 11\end{align*}$
::3x < 11

$\begin{align*}\text{-}5 < x \le \text{-}1\end{align*}$
::- 5<x__-1

$\begin{align*}\text{-}10< x < 14\end{align*}$
::-10 <x<14

$\begin{align*}2.6 < x < 8.4\end{align*}$
::2.6 <x<8.4

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::探索更多

$\begin{align*}6.75 \le t \le 8.25\end{align*}$ between 6 hours and 45 minutes, and 8 hours and 15 minutes
::6.751-8.25 6小时到45分钟之间,8小时到15分钟之间

$\begin{align*}1.2 \le x \le 1.4\end{align*}$ between 1 hour and 12 minutes, and 1 hour and 24 minutes
::1.2x1.4 1小时到12分钟之间,1小时到24分钟之间

$\begin{align*}\frac{4}{3} \le t \le 2\end{align*}$ between the 1 hour and 20 minutes and 2 hours
::从1小时到20分钟到2小时之间

$\begin{align*}11 \le d \le 13\end{align*}$ between $11 and $13
::11美元到13美元 11美元到13美元

An inequality of the OR-type where the intervals overlap. For example,
::时间间隔重叠的 OR 类型上的不平等。例如,

Section 2.9: Solving Absolute Value Equations

::第2.9节:解决绝对价值等量

Review
::回顾

x = 5, x = -11
::x = 5, x = -11

x = ± $\begin{align*}\frac{9}{2}\end{align*}$
::x = 92

x = -6, x = -9
::x = - 6, x = - 9 ;

x = 21, x = 9
::x = 21 x = 9

x = 30, x = -54
::x = 30, x = - 54

x = 5, x = $\begin{align*}-\frac{11}{7}\end{align*}$
::x = 5, x = -117

x = ± 20.5
::x = 20.5

x = 8, x = - $\begin{align*}\frac{1}{2}\end{align*}$
::x = 8, x = - 12

x = -5, x = $\begin{align*}\frac{55}{3}\end{align*}$
::x = 5-5, x = 553

$\begin{align*}\frac{3}{2}\end{align*}$

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29°

27 mpg
::27 mpg

least 168.748 cm, greatest 175.588 cm
::最小为168.748厘米,最大为175.588厘米

x = $\begin{align*}\frac{7}{2},\end{align*}$ x = $\begin{align*}\frac{5}{6}\end{align*}$
::x = 72, x = 56 = 72, x = 56

x = -1
::x=-1 = -1

Section 2.10: Solving Absolute Value Inequalities

::第2.10节:解决绝对价值不平等

Review
::回顾

$\begin{align*}x \ge 7 \end{align*}$ or $\begin{align*}x \le \text{-}7\end{align*}$
::x=7 或 x=7-7

$\begin{align*}\text{-}16.32 < x < 16.32\end{align*}$
::-16.32<x<16.32>

$\begin{align*}x < \text{-}\frac{3}{4}\end{align*}$ or $\begin{align*}x > \frac{3}{4}\end{align*}$
::x-34 或 x>34

$\begin{align*}x >6\end{align*}$ or $\begin{align*}x < \text{-}18\end{align*}$
::x6 或 x < 18

$\begin{align*}\text{-}7 \le x \le 25\end{align*}$
::- 7x25 - 7x25

$\begin{align*}x \ge 5\end{align*}$ or $\begin{align*}x \le 2\end{align*}$
::x% 5 或 x% 2

$\begin{align*}\text{-}\frac{11}{4} < x < 4\end{align*}$
::-114 <x <4

$\begin{align*}x > 6\end{align*}$ or $\begin{align*}x < \text{-}\frac{42}{5}\end{align*}$
::x6 或 x <-425

$\begin{align*}4 \le x \le 5\end{align*}$
::4x=5

$\begin{align*}x > 28\end{align*}$ or $\begin{align*}x < \text{-}\frac{20}{3}\end{align*}$
::x>28 或 x < 203

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The furthest you can travel is 550 in any direction, or x < -50 or x > 1,050.
::您可以旅行的最远处是任意方向550,或 x < -50 或 x > 1 050。

$\begin{align*}\left|98.6-x\right| \le 0.5 \; \; \text{or}\; \; \left|x - 98.6\right| \le 0.5\end{align*}$ , so 98.1°F ≤ T ≤ 99.1°F
::98.6-x 0.5 98.6 0.5, 所以98.1°F T 99.1°F

45.8% ≤ P ≤ 51.8% Yes, 51.1% is within the margin of error since it is a value in the inequality: 45.8% ≤ 51.1% ≤ 51.8%.
::45.8% 51.8% 是,51.1% 在误差幅度之内,因为它是不平等的价值:45.8% 51.1% 51.8%。

safe, $\begin{align*}\left|f\right| > 1.3;\end{align*}$ dangerous, $\begin{align*}\left|f\right| \le 1.3\end{align*}$
::安全,==========================================================================================================================================

Section 2.11: Translating Words into Algebra

::第2.11节:将单词转换成代数

Review
::回顾

x + (x + 1) = 79; x = 39, x + 1 = 40
::x + (x + 1) = 79; x = 39, x + 1 = 40

(2n + 1) + (2n + 3)= 44; 2n + 1 = 21, 2n + 3 = 23
:2n+1)+(2n+3)=44;2n+1=21;2n+3=23

2n + (2n + 2) + (2n + 4) = 138; 2n = 44, 2n + 2 = 46, 2n + 4 = 48
::2n + (2n+2) + (2n+4) = 138;2n = 44 2n + 2 = 46, 2n + 4 = 48

$7c – $2.75c = $500; 118 dozen cookies
::7c美元-2 75c美元=500美元;118打饼干

2w + 2(120*3) = 1,040; 160 feet or $\begin{align*}53\frac{1}{3}\end{align*}$ yards
::2w + 2(120*3)= 1 040;160英尺或5313码

2w + 2(w+20) = 120; width = 20 feet, length = 40 feet
::2w + 2(w+20) = 120;宽 = 20英尺,长度 = 40英尺

350 = 65h; 5.38 hours
::350=65小时;5.38小时

d = 65(2.5); 162.5 miles
::d=65(2.5);162.5英里

49.99 + 0.055(49.99); The cost of the sneakers with sales tax is $52.74. Yes, he can afford the sneakers, because $52.74 < $55.
::49.99 + 0.055(49.99);运动鞋的销售税费用为52.74美元。是的,他买得起运动鞋,因为52.74美元 < 55美元。

$\begin{align*}\frac{x}{100}\cdot 450\end{align*}$ ; 55.6%
::x100-450; 55.6%

14.2 答复----第2章:一个变量的线性等同和不平等

章节大纲

常规

回答 - Cch 2:一个变量的线性等同和不平等

Section 2.2: Solving One-Step Equations
::第2.2节:解决单级等号

Review
::回顾

Explore More
::探索更多

Section 2.3: Solving Two-Step Equations
::第2.3节:解决两层两层

Review
::回顾

Explore More

::探索更多

Section 2.4: Solving Multi-Step Equations

::第2.4节:解决多级数

Review
::回顾

Explore More
::探索更多

Section 2.5: Solving Equations for a Variable (Literal Equations)

::第2.5节:变量的溶解等量(标准等量)

Review
::回顾

Explore More
::探索更多

Section 2.6: Solving One- and Two-Step Inequalities
::第2.6节:解决一和二分不平等

Review
::回顾

Explore More
::探索更多

Section 2.7: Solving Multi-Step Inequalities
::第2.7节:解决多重不平等

Review
::回顾

Explore More

::探索更多

Section 2.8: Solving Compound Inequalities

::第2.8节:解决复合物不平等问题

Review
::回顾

Explore More
::探索更多

Section 2.9: Solving Absolute Value Equations

::第2.9节:解决绝对价值等量

Review
::回顾

Explore More

::探索更多

Section 2.10: Solving Absolute Value Inequalities

::第2.10节:解决绝对价值不平等

Review
::回顾

Explore More

::探索更多

Section 2.11: Translating Words into Algebra

::第2.11节:将单词转换成代数

Review
::回顾

章节大纲

常规

回答 - Cch 2:一个变量的线性等同和不平等

Section 2.2: Solving One-Step Equations ::第2.2节:解决单级等号

Review ::回顾

Explore More ::探索更多

Section 2.3: Solving Two-Step Equations ::第2.3节:解决两层两层

Review ::回顾

Explore More ::探索更多

Section 2.4: Solving Multi-Step Equations ::第2.4节:解决多级数

Review ::回顾

Explore More ::探索更多

Section 2.5: Solving Equations for a Variable (Literal Equations) ::第2.5节:变量的溶解等量(标准等量)

Review ::回顾

Explore More ::探索更多

Section 2.6: Solving One- and Two-Step Inequalities ::第2.6节:解决一和二分不平等

Review ::回顾

Explore More ::探索更多

Section 2.7: Solving Multi-Step Inequalities ::第2.7节:解决多重不平等

Review ::回顾

Explore More ::探索更多

Section 2.8: Solving Compound Inequalities ::第2.8节:解决复合物不平等问题

Review ::回顾

Explore More ::探索更多

Section 2.9: Solving Absolute Value Equations ::第2.9节:解决绝对价值等量

Review ::回顾

Explore More ::探索更多

Section 2.10: Solving Absolute Value Inequalities ::第2.10节:解决绝对价值不平等

Review ::回顾

Explore More ::探索更多

Section 2.11: Translating Words into Algebra ::第2.11节:将单词转换成代数

Review ::回顾

Section 2.2: Solving One-Step Equations
::第2.2节:解决单级等号

Review
::回顾

Explore More
::探索更多

Section 2.3: Solving Two-Step Equations
::第2.3节:解决两层两层

Review
::回顾

Explore More

::探索更多

Section 2.4: Solving Multi-Step Equations

::第2.4节:解决多级数

Review
::回顾

Explore More
::探索更多

Section 2.5: Solving Equations for a Variable (Literal Equations)

::第2.5节:变量的溶解等量(标准等量)

Review
::回顾

Explore More
::探索更多

Section 2.6: Solving One- and Two-Step Inequalities
::第2.6节:解决一和二分不平等

Review
::回顾

Explore More
::探索更多

Section 2.7: Solving Multi-Step Inequalities
::第2.7节:解决多重不平等

Review
::回顾

Explore More

::探索更多

Section 2.8: Solving Compound Inequalities

::第2.8节:解决复合物不平等问题

Review
::回顾

Explore More
::探索更多

Section 2.9: Solving Absolute Value Equations

::第2.9节:解决绝对价值等量

Review
::回顾

Explore More

::探索更多

Section 2.10: Solving Absolute Value Inequalities

::第2.10节:解决绝对价值不平等

Review
::回顾

Explore More

::探索更多

Section 2.11: Translating Words into Algebra

::第2.11节:将单词转换成代数

Review
::回顾