Section outline

  • lesson content

    Larry is building a skateboard ramp in his backyard. At first, he used a  3 8  inch thick piece of plywood. It didn't feel sturdy enough so he is replacing it with something that is  1 2  inch thicker that what he originally used. How thick will the ramp be? 
    ::拉里在后院建滑板坡。 起初, 他用了38英寸厚的胶合板。 感觉不够坚固, 所以他用比他原先使用的要厚12英寸的东西替换。 坡道会有多厚?

    In this concept, you will learn how to add fractions with different denominators. 
    ::在这个概念中,你会学习如何添加分数,分母不同。

    Adding Fractions with Different Denominators
    ::添加有不同分数的分数

    Fractions that have the same  denominator  have a  common denominator . To add fractions with a common denominator, you find the  sum  over the numerators over the common denominator. Not all addition problems will involve fractions with common denominators. 
    ::具有相同分母的分数有一个共同分母。要添加带有共同分母的分分数,您可以在共同分母上找到数字总和。并非所有添加问题都涉及带有共同分母的分数。

    Here is an addition problem.
    ::还有一个附加问题。

    1 2 + 1 4 = _

    One-half and one-fourth have different denominators and represent different quantities of a whole. 
    ::一半和四分之一的分母有不同的分母,代表一个整体的不同数量。

    lesson content

    lesson content

    To add fractions with different denominators, you will need to rewrite the fractions so that they have a common denominator before finding the sum.
    ::要添加具有不同分母的分数, 您需要重写分数, 以便在找到总和前有共同分母 。

    The first step is to the find the  least common multiple  (LCM) of the denominators, 2 and 4. Remember that the  LCM  is the smallest  multiple  that is shared by the numbers being compared. This LCM will become the  lowest common denominator  (LCD) for the fractions.
    ::第一步是找到分母中最小的多重(LCM),即2和4。 记住,LCM是被比较的数字所共享的最小的多个。 LCM将成为分数中最小的公分母(LCD)。

    List the multiples of 2 and 4.
    ::列出 2 和 4 的倍数。

    2: 2,  4 , 6, 8, 10 . . . 

    4:  4 , 8, 12, 16 . . . 

    The least common multiple of 2 and 4 is 4.
    ::2和4的最小常见乘数是4。

    Then, rewrite each fraction with the common denominator of 4. Multiply the  numerator  and the denominator of  1 2  by 2 to find the equivalent fraction..
    ::然后将每个分数重写为 4 的共同分母 。 乘以分子和1 2 2 的分母, 以找到相等的分母 。

    1 2 = 2 4

    The second fraction,  1 4 , is already written in terms of fourths.
    ::第二个分数,14, 已经以四分之一的写法写成。

    2 4 + 1 4

    Now you can add the fractions with common denominators. 
    ::现在您可以添加带有共同分母的分数 。

     

    2 4 + 1 4 = 3 4

    Finally,  simplify  the fraction, if possible. The  3 4  is a fraction in  simplest form
    ::最后,尽可能简化分数。3 4是最简单的分数。

    The sum is  3 4
    ::金额是3 4。

    You can add any number of fractions with unlike denominators as long as you rewrite the fractions with a common denominator.
    ::只要用共同的分母重写分母,您就可以添加含有不同分母的分数数。

    Examples
    ::实例

    Example 1
    ::例1

    Earlier, you were given a problem about Larry and his ramp.
    ::早些时候,你得到一个问题 关于拉里和他的斜坡。

    Larry started with  3 8  inch plywood, but wanted something  1 2  inch thicker. Add the measurements to find the total thickness of the ramp.
    ::拉里用38英寸的胶合板开始, 但想要更厚的12英寸。添加测量数据以找到斜坡的总厚度。

      3 8 + 1 2 = _

    First, check the denominators. The denominators are 8 and 2. The  LCD  is 8.
    ::首先,检查分母。分母是8和2。

    Then, rewrite the fractions with the common denominator.
    ::然后用共同分母重写分数。

      1 2 = 4 8

      3 8 + 4 8

    Next, add the fractions.
    ::下一步,添加分数。

      3 8 + 4 8 = 7 8

    The fraction is in simplest form.
    ::分数以最简单的形式出现。

    The skate ramp will be  7 8  inch thick.
    ::滑板斜坡将厚78英寸

    Example 2
    ::例2

    Find the sum.
    ::找到数额。

    2 7 + 3 9 = _

    First, check for a common denominator. The denominators are 7 and 9 and are not common. Find the LCD using the LCM of 7 and 9. 
    ::首先,检查一个共同的分母。 分母是 7 和 9 , 并不常见 。 请使用 7 和 9 的 LCM 查找 LCD 。

    7 – 7, 14, 21, 28, 35, 42, 49, 56,  63

    9 – 9, 18, 27, 36, 45, 54,  63

    The LCD is 63. 
    ::LCD是63岁。

    Then, rewrite the fractions. Find the   with the denominator 63.
    ::然后重写分数。 用分母63找到分母63。

    2 7 = 18 63 3 9 = 21 63

    18 63 + 21 63

    Next, add the fractions. Add the numerators over the common denominator.
    ::下一步,添加分数。在共同分母上添加分子。

    18 63 + 21 63 = 39 63

    Finally, simplify the fraction. The GCF of 39 and 63 is 3.   Divide  the numerator and the denominator by 3.
    ::最后,简化分数:全球合作框架39和63是3,分子和分母除以3。

      39 ÷ 3 63 ÷ 3 = 13 21

    The sum is  13 21 .
    ::总数是13 21。

    Example 3
    ::例3

    Find the sum:  1 2 + 2 6 = _ . Answer in simplest form.
    ::查找总和:1、2+2 6 = _。回答最简单。

    First, check the denominators. The denominators are 2 and 6. The LCD is 6.
    ::首先,检查分母,分母是2和6,液晶为6。

    Then, rewrite the fractions with the common denominator.
    ::然后用共同分母重写分数。

    1 2 = 3 6

      3 6 + 2 6

    Next, add the fractions.
    ::下一步,添加分数。

      3 6 + 2 6 = 5 6

    The fraction is in simplest form.
    ::分数以最简单的形式出现。

    The sum is  5 6 .
    ::总额是5 6。

    Example 4
    ::例4

    Find the sum:  2 3 + 1 9 = _ . Answer in simplest form.
    ::查找总和: 2 3+ 1 9 = _. 回答最简单。

    First, check the denominators. The denominators are 3 and 9. The LCD is 9.
    ::首先,检查分母。分母是3和9, 液晶显示器是9。

    Then, rewrite the fractions with the common denominator.
    ::然后用共同分母重写分数。

      2 3 = 6 9

      6 9 + 1 9

    Next, add the fractions.
    ::下一步,添加分数。

      6 9 + 1 9 = 7 9

    The fraction is in simplest form.
    ::分数以最简单的形式出现。

    The sum is  7 9 .
    ::金额是7 9。

    Example 5
    ::例5

    Find the sum:  4 5 + 1 3 = _ . Answer in simplest form.
    ::查找总和: 4 5 + 1 3 = _. 回答最简单。

    First, check the denominators. The denominators are 5 and 3. The LCD is 15.
    ::首先,检查分母。分母是5和3。 液晶显示器是15。

    Then, rewrite the fractions with the common denominator.
    ::然后用共同分母重写分数。

      4 5 = 12 15 1 3 = 5 15

      12 15 + 5 15

    Next, add the fractions.
    ::下一步,添加分数。

      12 15 + 5 15 = 17 15

    Finally, simplify the fraction. Convert the  improper fraction  to a  proper fraction .
    ::最后,简化分数,将不当分数转换成适当的分数。

    17 15 = 1 2 15

    The sum is  1 2 15 .
    ::金额是12 15。

    Review
    ::回顾

    Find the sum. Answer in simplest form.
    ::找到金额,回答最简单

    1. 3 4 + 1 2 = _  
    2. 6 7 + 1 2 = _  
    3. 2 3 + 1 3 = _  
    4. 2 3 + 1 6 = _  
    5. 1 2 + 1 8 = _
    6. 3 6 + 1 3 = _  
    7. 6 8 + 1 3 = _
    8. 4 7 + 1 2 = _
    9. 4 5 + 1 2 = _
    10. 3 7 + 1 6 = _
    11. 5 8 + 2 3 = _
    12. 6 7 + 1 3 = _
    13. 9 12 + 1 6 = _
    14. 8 10 + 1 2 = _
    15. 6 7 + 3 4 = _
    16. 3 4 + 2 6 = _

    Review (Answers) 
    ::回顾(答复)

    Click   to see the answer key or go to the Table of Contents and click on the Answer Key under the 'Other Versions' option.
    ::单击可查看答题键, 或转到目录中, 单击“ 其他版本” 选项下的答题键 。

    Resources
    ::资源