解决理性指数方程式
Section outline
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The period (in seconds) of a pendulum with a length of L (in meters) is given by the formula . If the period of a pendulum is is the length of the pendulum 156.8?
::P=2(L9.8)12的公式给出长于L(米)的钟表周期(秒)。如果钟表周期为10,则时长为156.8?Solving Rational Exponent Equations
::解决理性指数方程式When solving a rational exponent equation , you first isolate the variable . Then, to eliminate the exponent , you will need to raise everything to the reciprocal power.
::当解决一个理性的速率方程式时,你首先孤立变量。然后,为了消除指数,你需要将一切提升到对等权力。Let's determine if x = 9 is a solution to .
::让我们确定 x = 9 是 2x32-19 = 35 的解决方案 。Substitute in x and see if the equation holds.
::以 x 代替, 看看方程式是否有效 。9 is a solution to this equation.
::9是这个等式的解决方案。Now, let's solve the following equations for x.
::现在,让我们解决x的以下方程式。-
::3x52=96
First, divide both sides by 3 to isolate .
::首先,将双方除以3,分离x。
::3x52=96x52=32is raised to the five-halves power. To cancel out this exponent, we need to raise everything to the two-fifths power.
::X 被提升到五分之一的电源。 要取消这个提示, 我们需要将一切提升到五分之二的电源 。
:x5225=3225x=3225x=3252=22=4)
Check:
::查询: 3(4)52=325=332=96-
:2x-5-5)34+48202
Isolate by subtracting 48 and dividing by -2.
::孤立(x-5-5)34,减去48,除以-2。
::- (x-5)34+48202-2(x-5)34250(x-5)34125To undo the three-fourths power, raise everything to the four-thirds power.
::为了推翻四分之三的权力, 将一切提升到四分之三的权力。
::[(x-5)34]43=(-125)43x-5=625x=630Check:
::检查:- (2) 630- 5) 34+48 @2} @262534+48}2125+48}250+48202Examples
::实例Example 1
::例1Earlier, you were asked to verify the length of the pendulum.
::早些时候,有人要求你核查钟摆的长度。We need to plug 156.8 in to the equation for L and solve. If our answer equals , then the given length is correct.
::我们需要将156.8插入L的 P=2Q(L9.8)12 等式并解析。 如果我们的答案等于 10Q, 那么给定的长度是正确的 。
::P=2(L9.8) 122(156.89.8) 122(16) 122(4)=8does not equal , so the length cannot be 156.8.
::8不等于10,所以长度不能为156.8。Solve the following rational exponent equations and check for extraneous solutions.
::解决以下合理的推理方程式,并检查不相干的解决办法。Example 2
::例2
::8(3x-1)23=200Divide both sides by 8 and raise everything to the three-halves power.
::将两边除以8 把每样东西都加到三座的威力上
::8( 3x- 1) 23=200[ (3x- 1) 23] 32=( 25) 323x- 1=1=1253x=126x=42Check:
::检查: 8( 3( 42) - 1) 23= 8( 126) - 1) 23= 8( 125) 23= 8( 8) 25= 200Example 3
::例32.
::6x32-141=19172。Here, only the is raised to the three-halves power. Subtract 141 from both sides and divide by 6. Then, eliminate the exponent by raising both sides to the two-thirds power.
::在这里, 只有 x 才能升到三座。 从两侧减141 , 然后除以 6 。 然后, 通过 将 双方 提升到 三分之二 的 权力 来消除 引力 。
::6x32-141=19176x32=2058x32=343x=343x=34323=72=49Check:
::查询: 6( 4932) -141=6}343 -141=2058 - 141=1917Review
::回顾Determine if the following values of x are solutions to the equation
::确定以下 x 值是否是方程 3x35 的解决方案 24-
::x=32x=32 -
::x32 -
::x=8x=8
Solve the following equations. Round any decimal answers to 2 decimal places.
::解决以下方程式。 将小数点后的任何答案四舍五入到小数点后两位 。-
::2x32=54 -
::3x13+5=17 -
:7x-3)25=4
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:4x+5)12=x-4
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::x52=16x12 -
:5x+7)35=8
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::5x23=45 -
:7x-8)23=4(x-5)23
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::7x37+9=65 -
::4997=5x32-3 -
::2x34=686 -
::x3=( 4x-3) 32
Review (Answers)
::回顾(答复)Click to see the answer key or go to the Table of Contents and click on the Answer Key under the 'Other Versions' option.
::单击可查看答题键, 或转到目录中, 单击“ 其他版本” 选项下的答题键 。 -