Section outline

  • Two-Column Proofs
    ::两色证明

    A two-column proof is one common way to organize a proof in geometry. Two-column proofs always have two columns: one for statements and one for reasons. The best way to understand two-column proofs is to read through examples.
    ::两栏证明是组织几何证据的一种常见方法。 两栏证明总是有两栏:一栏用于说明,一栏用于理由。理解两栏证明的最佳方法是通过实例阅读。

    When writing your own two-column proof, keep these things in mind:
    ::写出自己的两栏证明时, 请记住:

    • Number each step.
      ::每个步骤的数目。
    • Start with the given information.
      ::以给定的信息开始 。
    • Statements with the same reason can be combined into one step . It is up to you.
      ::理由相同的语句可以合并为一步,由你决定。
    • Draw a picture and mark it with the given information.
      ::绘制图片并用给定的信息标记它 。
    • You must have a reason for EVERY statement.
      ::你必须有一个理由 每一个声明。
    • The order of the statements in the proof is not always fixed, but make sure the order makes logical sense.
      ::证据中的语句顺序并不总是固定的,但要确保顺序合乎逻辑。
    • Reasons will be definitions, postulates, properties and previously proven theorems. “Given” is only used as a reason if the information in the statement column was given  in the problem.
      ::理由将是定义、假设、属性和以前证明的理论。 “给予”只有在说明栏中的信息是在问题中提供的时才被用作理由。
    • Use symbols and abbreviations for words within proofs. For example, can be used in place of the word congruent . You could also use for the word angle .
      ::使用符号和缩略语表示在 校对 中的单词 。 例如, \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\可以\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

    Suppose you are told that X Y Z is a right angle and that Y W bisects X Y Z . You are then asked to prove X Y W W Y Z .
    ::假设你被告知 XYZ是一个正确的角度 和YWQ 的两块 XYZ。然后你被要求证明 XYWWWWYZ。

    Examples
    ::实例

    Example 1
    ::例1

    Write a two-column proof for the following:
    ::为下列事项写两栏证明:

    If A , B , C , and D are points on a line , in the given order, and A B = C D , then A C = B D .
    ::如果A、B、C和D是线上的点,则按给定顺序排列,AB=CD,然后是AC=BD。

    When the statement is given in this way, the “if” part is the given and the “then” part is what we are trying to prove.
    ::当以这种方式作出声明时,“如果”部分是给的,“当时”部分是我们试图证明的。

    Always start with drawing a picture of what you are given.
    ::总是从绘制给定内容的图片开始 。

    Plot the points in the order A , B , C , D on a line.
    ::按A、B、C、D顺序排列点数。

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    Add the given, A B = C D .
    ::添加给定的,AB=CD。

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    Draw the two-column proof and start with the given information.
    ::绘制两栏证明,并用给定的信息开始。

    Statement Reason
    1. A , B , C , and D are collinear , in that order. 1. Given
    2. A B = C D 2. Given
    3. B C = B C 3. Reflexive P o E
    4. A B + B C = B C + C D 4. Addition P o E

    5. A B + B C = A C
    ::5. AB+BC=AC

    B C + C D = B D
    ::BC+CD=BD (BC+CD=BD)

    5. Segment Addition Postulate
    6. A C = B D 6. Substitution or Transitive P o E

    Example 2
    ::例2

    Write a two-column proof.
    ::写两栏证明书

    Given : B F bisects A B C ; A B D C B E
    ::参考:BF-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-B-B-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-B-B-AB-AB-AB-AB-AB-AB-AB-B-B-B-B-B-B-B-B-B-B-B-B-B-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-AB-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-B-

    Prove : D B F E B F
    ::证明: DBF_EBF

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    First, put the appropriate markings on the picture. Recall, that bisect means “to cut in half.” Therefore, m A B F = m F B C .
    ::首先,在照片上贴上适当的标记。回顾,这个两部分的意思是“切成两半”。 因此,MABF=mFBC。

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    Statement Reason
    1. B F bisects A B C , A B D C B E 1. Given
    2. m A B F = m F B C 2. Definition of an Angle Bisector
    3. m A B D = m C B E 3. If angles are , then their measures are equal.

    4. m A B F = m A B D + m D B F
    ::4. mABF=mABD+mDBF

    m F B C = m E B F + m C B E
    ::mFBC=mEBF+mCBE FBC=mEBF+mCBE FBC=mEBF+mCBE

    4. Angle Addition Postulate
    5. m A B D + m D B F = m E B F + m C B E 5. Substitution P o E
    6. m A B D + m D B F = m E B F + m A B D 6. Substitution P o E
    7. m D B F = m E B F 7. Subtraction P o E
    8. D B F E B F 8. If measures are equal, the angles are .

    Example 3
    ::例3

    The Right Angle Theorem states that if two angles are right angles, then the angles are congruent. Prove this theorem .
    ::右角角定理指出,如果两个角度是右角,那么角度是相同的。 证明这个定理 。

    To prove this theorem, set up your own drawing and name some angles so that you have specific angles to talk about.
    ::为了证明这个定理, 设置您自己的绘图, 并指定一些角度, 这样您就可以有具体的角度来讨论 。

    Given : A and B are right angles
    ::给出: A 和 B 是正确角度

    Prove : A B
    ::证明: @AB

    Statement Reason
    1. A and B are right angles 1. Given
    2. m A = 90 and m B = 90 2. Definition of right angles
    3. m A = m B 3. Transitive P o E
    4. A B 4. angles have = measures

    Any time right angles are mentioned in a proof, you will need to use this theorem to say the angles are congruent.
    ::每当在证据中提及右角度时, 您需要使用此定理来表示角度一致 。

    Example 4
    ::例4

    The Same Angle Supplements Theorem states that if two angles are supplementary to the same angle then the two angles are congruent. Prove this theorem.
    ::同一角补充理论指出,如果两个角度是同一角度的补充,那么这两个角度是相同的。证明这个理论。

    Given : A and B are . B and C are supplementary angles.
    ::说明:A和B是.B和C是补充角度。

    Prove : A C
    ::证明:

    Statement Reason

    1. A and B are supplementary
    ::1. A和B是补充

    B and C are supplementary
    ::B和C是补充

    1. Given

    2. m A + m B = 180
    ::2. mA+mB=180

    m B + m C = 180
    ::mB+mC=180\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\C\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

    2. Definition of supplementary angles
    3. m A + m B = m B + m C 3. Substitution P o E
    4. m A = m C 4. Subtraction P o E
    5. A C 5. angles have = measures

    Example 5
    ::例5

    The Vertical Angles Theorem states that are congruent. Prove this theorem.
    ::垂直角定理显示相似。 证明这个定理 。

    Given : Lines k and m intersect.
    ::K线和m线交叉。

    Prove: 1 3
    ::证明:% 1 @% 3

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    Statement Reason
    1. Lines k and m intersect 1. Given

    2. 1 and 2 are a linear pair
    ::2. 1和2是线性对

    2 and 3 are a linear pair
    ::2和3是线性对

    2. Definition of a Linear Pair

    3. 1 and 2 are supplementary
    ::3.1和2是补充性的

    2 and 3 are supplementary
    ::2和3是补充

    3. Linear Pair Postulate

    4. m 1 + m 2 = 180
    ::m1+m2=180

    m 2 + m 3 = 180
    ::m2+m3=180

    4. Definition of Supplementary Angles
    5. m 1 + m 2 = m 2 + m 3 5. Substitution P o E
    6. m 1 = m 3 6. Subtraction P o E
    7. 1 3 7. angles have = measures

    Example 6
    ::例6

    1 4 and C and F are right angles.
    ::14 和 C 和 F 是正确角度。

    Which angles are congruent and why?
    ::哪个角度是一致的,为什么?

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    By the Right Angle Theorem, C F . Also, 2 3 by the Same Angles Supplements Theorem because 1 4 and they are linear pairs with these congruent angles.
    ::以右角角定理为依归, 也以同角定理为依归, 因为它们是线性对子,

    Review
    ::回顾

    Fill in the blanks in the proofs below.
    ::填充以下证据中的空白。

    1. Given: A B C D E F and G H I J K L
      ::来源:@ABCDEF和GHIJKL

    Prove: m A B C + m G H I = m D E F + m J K L
    ::证明:mABC+mGHI=mDEF+mJKL

    Statement Reason
    1. 1. Given

    2. m A B C = m D E F
    ::2. mABC=mDEF

    m G H I = m J K L
    ::

    2.
    3. 3. Addition P o E
    4. m A B C + m G H I = m D E F + m J K L 4.
    1. Given: M is the midpoint of A N ¯ . N is the midpoint M B ¯
      ::表示:M是 AN的中点。N是中点MB

    Prove : A M = N B
    ::证明:AM=NB

    Statement Reason
    1. Given
    2. Definition of a midpoint
    3. A M = N B
    1. Given: A C ¯ B D ¯ and 1 4
      ::依据:AC =BD 和14

    Prove : 2 3
    ::证明:% 2 @% 3

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    Statement Reason
    1. A C ¯ B D ¯ , 1 4 1.
    2. m 1 = m 4 2.
    3. 3. lines create right angles

    4. m A C B = 90
    ::4. mACB=90___________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

    m A C D = 90
    ::máACD=90

    4.

    5. m 1 + m 2 = m A C B
    ::m1+m2=mACB

    m 3 + m 4 = m A C D
    ::3+m4=mACD

    5.
    6. 6. Substitution
    7. m 1 + m 2 = m 3 + m 4 7.
    8. 8. Substitution
    9. 9.Subtraction P o E
    10. 2 3 10.
    1. Given: M L N O L P
      ::参照:*MLNOLP

    Prove : M L O N L P
    ::证明:

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    Statement Reason
    1. 1.
    2. 2. angles have = measures
    3. 3. Angle Addition Postulate
    4. 4. Substitution
    5. m M L O = m N L P 5.
    6. 6. angles have = measures
    1. Given: A E ¯ E C ¯ and B E ¯ E D ¯
      ::以: AE EC 并被锁定

    Prove : 1 3
    ::证明:

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    Statement Reason
    1. 1.
    2. 2. lines create right angles

    3. m B E D = 90
    ::3. mBED=90

    m A E C = 90
    ::mAEC=90

    3.
    4. 4. Angle Addition Postulate
    5. 5. Substitution
    6. m 2 + m 3 = m 1 + m 3 6.
    7. 7. Subtraction P o E
    8. 8. angles have = measures
    1. Given: L is supplementary to M and P is supplementary to O and L O
      ::因此:L是M的补充,P是O和LO的补充。

    Prove : P M
    ::证明:

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    Statement Reason
    1. 1.
    2. m L = m O 2.
    3. 3. Definition of supplementary angles
    4. 4. Substitution
    5. 5. Substitution
    6. 6. Subtraction P o E
    7. M P 7.
    1. Given: 1 4
      ::百分比:%1%4

    Prove : 2 3
    ::证明:% 2 @% 3

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    Statement Reason
    1. 1.
    2. m 1 = m 4 2.
    3. 3. Definition of a Linear Pair

    4. 1 and 2 are supplementary
    ::4.1和2是补充性的

    3 and 4 are supplementary
    ::3和4是补充

    4.
    5. 5. Definition of supplementary angles
    6. m 1 + m 2 = m 3 + m 4 6.
    7. m 1 + m 2 = m 3 + m 1 7.
    8. m 2 = m 3 8.
    9. 2 3 9.
    1. Given: C and F are right angles
      ::给定: C 和F 是正确角度

    Prove : m C + m F = 180
    ::证明: mC+mF=180{____________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

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    Statement Reason
    1. 1.
    2. m C = 90 , m F = 90 2.
    3. 90 + 90 = 180 3.
    4. m C + m F = 180 4.
    1. Given: l m
      ::来源:百分比

    Prove : 1 2
    ::证明:%1 @%2

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    Statement Reason
    1. l m 1.
    2. 1 and 2 are right angles 2.
    3. 3.
    1. Given: m 1 = 90
      ::百分比: m1=90

    Prove : m 2 = 90
    ::证明: m2=90

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    Statement Reason
    1. 1.
    2. 1 and 2 are a linear pair 2.
    3. 3. Linear Pair Postulate
    4. 4. Definition of supplementary angles
    5. 5. Substitution
    6. m 2 = 90 6.
    1. Given: l m
      ::来源:百分比

    Prove : 1 and 2 are complements
    ::证明:%1和%2是补充

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    Statement Reason
    1. 1.
    2. 2. lines create right angles
    3. m 1 + m 2 = 90 3.
    4. 1 and 2 are complementary 4.
    1. Given: l m and 2 6
      ::来源: lm 和 26

    Prove : 6 5
    ::证明:% 6 @% 5

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    Statement Reason
    1. 1.
    2. m 2 = m 6 2.
    3. 5 2 3.
    4. m 5 = m 2 4.
    5. m 5 = m 6 5.

    Review (Answers)
    ::回顾(答复)

    Click to see the answer key or go to the Table of Contents and click on the Answer Key under the 'Other Versions' option.
    ::单击可查看答题键, 或转到目录中, 单击“ 其他版本” 选项下的答题键 。