8.9 对数权财产
Section outline
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The hypotenuse of a right triangle has a length of . How long is the triangle's hypotenuse?
::右三角形的下限长度为 log3 278. 三角形的下限持续多久?Power Property
::电力产权The last property of logs is the Power Property .
::原木的最后一项财产是电力财产。
::对数bx=yUsing the definition of a log, we have . Now, raise both sides to the power.
::使用日志的定义, 我们有 by=x 。 现在, 将两边都提升到 n权力 。
:n)n=xnbny=xn)
Let’s convert this back to a log with base , . Substituting for , we have .
::让我们将此转换为 b, logb_xn=ny 的日志。 替换 y, 我们有logb_xn=nlogb_x 。Therefore, the Power Property says that if there is an exponent within a logarithm, we can pull it out in front of the logarithm.
::因此,电力财产公司说,如果在对数内有一个推算符,我们可以在对数前把它拉出来。Let's u se the Power Property to expand the following logarithms.
::让我们利用电力财产来扩大以下对数。-
::对数 6\\\\\17x5
To expand this log, we need to use the Product Property and the Power Property.
::为了扩大这一日志,我们需要使用产品产权和电力产权。
::对数 6\\\ 17x5=log6\\ 17+log6\\\ x5=log6\\ 17+5log6\ xx-
::In( 2xy3) 4
We will need to use all three properties to expand this problem. Because the expression within the natural log is in parenthesis, start with moving the power to the front of the log.
::我们需要使用所有三个属性来扩大这个问题。 因为自然日志中的表达方式在括号中, 开始将第四电源移到日志前端 。
::In( 2xy3) 4= 4ln2xy3= 4( ln2x- ln3) = 4( ln2+lnx- 3ln) = 4ln2+4ln1x-12lnDepending on how your teacher would like your answer, you can evaluate , making the final answer .
::取决于您的老师对您答案的满意程度, 您可以评估 4ln22. 77, 得出最后答案 2. 77+4lnx- 12lny 。Now, let's condense .
::现在,让我们来压缩对数\\\\4log\5 -4log\5\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\"\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\This is the opposite of the previous two problems . Start with the Power Property.
::这与前两个问题正好相反。 从电力财产开始。
::\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\8\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\可以\\\\\\\\\\\\\\\\\\\Now, start changing things to division and multiplication within one log.
::现在,开始把事情改变成一个日志内的分割和乘法。
::log=% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =% =%Lastly, combine like terms.
::最后,将类似术语结合起来。
::log441y2625x4Examples
::实例Example 1
::例1Earlier, you were asked to find the length of the triangle's hypotenuse.
::早些时候,有人要求你 找到三角形的下垂长度We can rewrite and and solve.
::我们可以重写对数3278和8log327 并解决。
::8log327=83=24Therefore, the triangle's hypotenuse is 24 units long.
::因此三角形的下限是24单位长Example 2
::例2Expand the following expression: .
::展开以下表达式: Inx3 。The only thing to do here is apply the Power Property: .
::这里唯一需要做的是应用电力财产:3lnx。Example 3
::例3Expand the following expression: .
::展开以下表达式: log16\\ x2y32z5。Let’s start with using the Quotient Property.
::让我们从引用属性开始。
::对数 16\\ x2y32z5=log16\ x2y-log16\\\32z5Now, apply the Product Property, followed by the Power Property.
::现在,应用产品产权,然后是电力产权。
::=log16_x2+log16_y_(log16_32+log16_z5)=2log16_x+log16_y_54_5log16_zSimplify and solve for . Also, notice that we put parenthesis around the second log once it was expanded to ensure that the would also be subtracted (because it was in the denominator of the original expression).
::简化对数 163216n=3224n=25 并解决n. 另外,请注意,在扩展第二个日志以确保Z5也减去后,我们将在第二个日志上加括号(因为它是原表达式的分母)。Example 4
::例4Expand the following expression: .
::展开以下表达式: log( 5c4) 2。For this problem, you will need to apply the Power Property twice.
::对于这个问题,您需要两次使用电力财产。
::log*5c4=2log*5c4=2(log*5+log*4)=2(log*5+4log*4c)=2log*5+8log*c)=2log*5+8log*cImportant Note: You can write this particular log several different ways. Equivalent logs are: and . Because of these properties, there are several different ways to write one logarithm.
::重要注意 : 您可以以几种不同的方式写入此特定日志 。 等值日志是: log\ 25+8logc, log\ 25+logc8 和 log\ 25c8. 由于这些属性, 有几种不同的方式来写入一个对数 。Example 5
::例5Condense into one log: .
::整合成一个日志 : 5 - 7ln x4+2ln y 。To condense this expression into one log, you will need to use all three properties.
::要将这个表达式压缩成一个日志, 您需要使用所有三个属性 。
::5 - 7ln_ x4+2ln_ y=ln_ 5 - ln_ x28+ln_ y2=ln_ 5y2x28Important Note: If the problem was , then the answer would have been . But, because there are no parentheses, the is in the numerator.
::重要注意: 如果问题在于 In5-( 7lnx4+2lny) , 那么答案应该是 nn5x28y2。 但是, 因为没有括号, y2 在数字中 。Review
::回顾Expand the following logarithmic expressions.
::展开以下对数表达式。-
::对数 7\\\y2 -
::对数 12\\\\5z2 -
::对数 4( 9x) 3 -
::log *( 3xy) 2 -
::对数 8x3y2z4 -
::对数 5( 25x4y) 2 -
:6xy3) -2
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::内(e5x-2y3)6
Condense the following logarithmic expressions.
::包含以下对数表达式 。-
::6logx -
::2log6x+5log6y -
::3(logx-logy) -
::12log( x+1) - 3log -
::4log2y+13log2x3 -
::15[10log2(x-3)+log232-log2 -
::4[12log3]-13log3]-x-log3z]
Review (Answers)
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