Section outline

  • The power rule is a fantastic "shortcut" for finding the of basic polynomials. Between the power rule and the basic definition of the derivative of a constant, a great number of polynomial derivatives can be identified with little effort - often in your head!
    ::权力规则是寻找基本多边协议的绝妙的“捷径 ” 。 在权力规则和常数衍生物的基本定义之间,大量多边协议衍生物可以毫不费力地被识别出来 — — 通常在你的脑中!

    Constant Derivatives and the Power Rule
    ::经常衍生物和权力规则

    In this lesson, we will develop formulas and theorems that will calculate derivatives in more efficient and quick ways. Look for these theorems in boxes throughout the lesson.
    ::在此教训中, 我们将开发公式和定理, 以更高效、 更快捷的方式计算衍生物。 在整个课程中查找框中的这些定理 。

    The Derivative of a Constant
    ::常数的衍生因素

    Theorem: If f ( x ) = c where c is a constant, then f ( x ) = 0 .
    ::定理 : 如果 f( x) =c 的 c 是常数, 那么 f_( x) =0 。

    Proof: f ( x ) = lim h 0 f ( x + h ) f ( x ) h = lim h 0 c c h = 0 .
    ::校对:f_(x)=limh_0f(x+h)-f(x)h=limh_0c-ch=0。

    Theorem: If c is a constant and f is differentiable at all x , then d d x [ c f ( x ) ] = c d d x [ f ( x ) ] . In simpler notation ( c f ) = c ( f ) = c f

    The Power Rule
    ::权力规则

    Theorem: (The Power Rule) If n is a positive integer, then for all real values of x
    d d x [ x n ] = n x n 1 .

    Examples
    ::实例

    Example 1
    ::例1

    Find f ( x ) for f ( x ) = 16 .
    ::查找 f( x) =16 的 f_( x) 。

    If f ( x ) = 16 for all x , then f ( x ) = 0 for all x .
    ::如果 f( x) =16 全部 x, 那么 f_( x) =0 全部 x 。

    We can also write d d x 16 = 0 .
    ::我们还可以写入 ddx16=0 。

    Example 2
    ::例2

    Find the derivative of f ( x ) = 4 x 3 .
    ::查找 f( x) =4x3 的衍生物 。

    d d x [ 4 x 3 ] ..... Restate the function
    ::ddx[4x3] ....

    4 d d x [ x 3 ] ..... Apply the commutative law
    ::4ddx[x3] ....应用通货法

    4 [ 3 x 2 ] ..... Apply the power Rule
    ::4[3x2].应用权力规则

    12 x 2 ..... Simplify
    ::12x2.... 简化

    Example 3
    ::例3

    Find the derivative of f ( x ) = 2 x 4 .
    ::查找 f (x)\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\F\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\F\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\F\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

    d d x [ 2 x 4 ] ..... Restate
    ::ddx[- 2x4] .... 重报

    d d x [ 2 x 4 ] ..... Rules of exponents
    ::ddx[-2x-4]. 引言人规则

    2 d d x [ x 4 ] ..... By the commutative law
    ::-2dx[x-4].根据通货法

    2 [ 4 x 4 1 ] ..... Apply the power rule
    ::--2[-4x-4-1] ...。应用权力规则

    2 [ 4 x 5 ] ..... Simplify
    ::--2[-4x-5]. 简化

    8 x 5 ..... Simplify again
    ::8x-5. 再次简化

    8 x 5 ..... Use rules of exponents
    ::8x5. 使用指数者的规则

    Example 4
    ::例4

    Find the derivative of  f ( x ) = x .
    ::查找 f( x) =x 的衍生物 。

    Special application of the power rule:
    ::权力规则的特殊适用:

    d d x [ x ] = 1 x 1 1 = x 0 = 1
    ::ddx[x]=1x1 -1=x0=1

    Example 5
    ::例5

    Find the derivative of  f ( x ) = x .
    ::查找 f( x) =x 的衍生物 。

    Restate the function: d d x [ x ]
    ::复述函数: ddx[x]

    Using rules of exponents (from algebra): d d x [ x 1 / 2 ]
    ::使用前言规则( 取自代数) : ddx [x1/ 2]

    Apply the power rule: 1 2 x 1 / 2 1
    ::应用权力规则: 12x1/2- 1

    Simplify: 1 2 x 1 / 2
    ::简化: 12x-1/2

    Rules of exponents: 1 2 x 1 / 2
    ::规则:12x1/2

    Simplify: 1 2 x
    ::简化: 12x

    Example 6
    ::例6

    Find the derivative of  f ( x ) = 1 x 3 .
    ::查找 f( x) = 1x3 的衍生物 。

    Restate the function: d d x [ 1 x 3 ]
    ::复述函数: ddx[1x3]

    Rules of exponents: d d x [ x 3 ]
    ::引言人规则: ddx[x-3]

    Power rule: 3 x 3 1
    ::权力规则:-3x-3-3-1

    Simplify: 3 x 4
    ::简化:- 3x- 4

    Rules of exponents: 3 x 4
    ::引言人规则:-3x4

    Review
    ::回顾

    1. State the power rule.
      ::国家的权力统治。

    Find the derivative:
    ::查找衍生物 :

    1. y = 5 x 7
      ::y=5x7 y=5x7
    2. y = 3 x
      ::y 3x
    3. f ( x ) = 1 3 x + 4 3
      :sadxx)=13x+43
    4. y = x 4 2 x 3 5 x + 10
      ::y=x4 - 2x3 - 5x+10 y=x4 - 2x3 - 5x+10
    5. y = ( 5 x 2 3 ) 2
      ::y=( 5x2- 3) 2
    6. Given y ( x ) = x 4 π 2 , find the derivative when x = 1 .
      ::give y(x) =x- 42, 在 x=1 时找到衍生物 。
    7. y ( x ) = 5
      ::y(x)=5
    8. Given u ( x ) = x 5 π 3 , what is u ( 2 ) ?
      ::鉴于 u(x) =x-53,什么是 u(2)?
    9. Given  d ( x ) = x 0.37 , what is d ( 1 ) ?
      ::鉴于d(x)=x-0.37,什么是d(1)?
    10. g ( x ) = x 3
      ::g(x)=x-3
    11. u ( x ) = x 0.096
      ::u(x)=x0.096
    12. k ( x ) = x 0.49
      :sadxx)=x-0.49
    13. y = x 5 π 3
      ::y=x - 5=3

    Review (Answers)
    ::回顾(答复)

    Click to see the answer key or go to the Table of Contents and click on the Answer Key under the 'Other Versions' option.
    ::单击可查看答题键, 或转到目录中, 单击“ 其他版本” 选项下的答题键 。