章节大纲

  • In This Lesson
    ::在本课程中

    You will calculate the probability of compound events in the context of game shows.
    ::您将在游戏显示的背景下计算复合事件的概率 。

     


    Deal or No Deal
    ::发牌或未发牌或未发牌

    Nearly twenty years ago, a Dutch television game show called 'Hunt for Millions' was created. The game was based on contestants guessing which of many cases held the most money, without looking in the cases until after they were eliminated. The show was a great success, and later was duplicated in many countries, including the U.S.A. The show, which premiered in 2005, was renamed "Deal or No Deal" and is hosted by comedian Howie Mandel.
    ::近20年前,荷兰制作了一个名为“为百万人打猎 ” 的电视游戏节目。 这场比赛基于参赛者猜想,在很多案件中,哪些案件拥有最多的钱,而没有看完这些案子,直到这些案子被消灭。 这场比赛取得了巨大成功,后来在包括美国在内的许多国家被复制。 2005年首演的这个节目被改名为“决定还是不交易 ” , 由喜剧演员Howie Mandel主持。

    Here, you will have a chance to play a smaller version of the game by yourself! You start with four cases, and in each 'round,' choose one case to remove from the table. The goal is to try to leave the case with $10,000 for last.
    ::在这里, 您将有机会独自玩一个较小版本的游戏 。 您先从四个案子开始, 在每个“ 回合 ” 中, 选择一个案子从桌面上删除 。 目标是尝试将一个案子的一万美元留在最后 。

    Play  the " Deal or No Deal " game in   the interactive below several times. R eview  the tree diagram and the probability of each final outcome at the end of the game. Once you have a feel for the probabilities of each  prize,   answer the inline  questions that follow .
    ::在下面的交互游戏中玩“ 交易或无交易” 游戏。 请在游戏结束时查看树形图和每个最终结果的概率。 一旦您对每个奖项的概率有感觉, 请回答下面的线性问题 。

     

    INTERACTIVE
    Briefcase Cash!
    minimize icon

    One of these briefcases contains a jackpot of $10,000! Eliminate three cases and open the last case to see your prize!
    ::其中一个公文包里有一大笔一万美金!

    • Click on a case to eliminate it. 
      ::点击一个案例来消除它 。
    • Click the buttons after to see tree diagram and try again.
      ::单击之后的按钮查看树形图并再试一次。

    What is the probability of opening the jackpot after one case is eliminated, after two cases and after three?
    ::在一个案件被消除、两个案件被消除、三个案件被消除之后,开启大奖的概率有多大?

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    You Win a Car!
    ::你赢了车!

    Imagine a game show called "The Price is Nearly Correct." In order to win a car, the contestant must guess the price of the car in one try.
    ::试想一下一个叫“价格几乎正确”的游戏节目。为了赢得一辆车,参赛者必须猜一猜车价。

    The contestant is given 5 digits, each is one away from the actual  value  in the price of the car. The contestant has to determine if  the actual   value is one above or  one  below the given digit . What is the probability that the contestant will win the car in one try?
    ::参赛者获得5位数, 每一位数离汽车价格的实际值相差1位。参赛者必须确定实际值是高于1位数还是低于给定数。 参赛者一次赢得汽车的概率是多少?

    • Use the  arrows above and below each digit to change them.
      ::使用每个位数以上和下方的箭头来改变它们 。
    • Once you have changed each number, click on the "How many are correct?" button.  This will tell you how many digits are correct. It will not tell you which ones are correct, though!
      ::一旦您更改了每个数字, 请点击“ 多少数字正确 ” 按钮。 这将告诉您多少位数字正确 。 它不会告诉你哪些数字正确 !
    • Keep changing the digits and checking until you have successfully guessed the price of the car . How many trials did it take you?
      ::继续更改数字和检查,直到你成功地猜出车价。你花了多少次试验?
    INTERACTIVE
    Not Exactly
    minimize icon
    • Press the buttons with arrows to choose a digit above or below the current one to figure out the price of a car.
      ::按下带有箭头的按钮以选择当前数字以上或下的数字来计算汽车的价格。
    • Press the white button at the bottom of the interactive to see how many digits match the actual price of the car.
      ::按下互动的底部的白色按钮, 看看有多少位数符合汽车的实际价格 。
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    robability-of-compound-events" quiz-url="https://www.ck12.org/assessment/ui/embed.html?test/view/5f455830dbfde89a8aafbfb5&collectionHandle=probability&collectionCreatorID=3&conceptCollectionHandle=probability-:吐舌头robability-of-compound-events&mode=lite" test-id="5f455830dbfde89a8aafbfb5">

     

    Discussion Question
    ::讨论问题

    If the chance of winning is so low, why would people  want to go on this game show? Would you ever consider going on a game show like this? 
    ::如果赢的机会如此之低,为什么人们想上这个游戏节目?你考虑过这样的游戏节目吗?

      Summary
    ::摘要

    • To determine the probability of a compound event, multiply the probabilities of each of the simple events occurring together.
      ::为确定复合事件的概率,乘以一起发生的每个简单事件的概率。